9x^2-153x+144=0

Solution for 9x^2-153x+144=0 equation:

9x^2-153x+144=0

a = 9; b = -153; c = +144;
Δ = b2-4ac
Δ = -1532-4·9·144
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18225}=135$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-153)-135}{2*9}=\frac{18}{18}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-153)+135}{2*9}=\frac{288}{18}
=16
$